![abstract algebra - How to prove that as an $R$-module, $\mathbb{C}^n$ is finitely generated iff $R=\mathbb{C}[x]$. - Mathematics Stack Exchange abstract algebra - How to prove that as an $R$-module, $\mathbb{C}^n$ is finitely generated iff $R=\mathbb{C}[x]$. - Mathematics Stack Exchange](https://i.stack.imgur.com/xxHJE.png)
abstract algebra - How to prove that as an $R$-module, $\mathbb{C}^n$ is finitely generated iff $R=\mathbb{C}[x]$. - Mathematics Stack Exchange
![PDF) Structure Theorem for Rings Whose Finitely Generated Modules are Direct Sums of Virtually Simple Modules PDF) Structure Theorem for Rings Whose Finitely Generated Modules are Direct Sums of Virtually Simple Modules](https://i1.rgstatic.net/publication/303699358_Structure_Theorem_for_Rings_Whose_Finitely_Generated_Modules_are_Direct_Sums_of_Virtually_Simple_Modules/links/574efd3408aef199238c053a/largepreview.png)
PDF) Structure Theorem for Rings Whose Finitely Generated Modules are Direct Sums of Virtually Simple Modules
![abstract algebra - Proofs of the structure theorem for finitely generated modules over a PID - Mathematics Stack Exchange abstract algebra - Proofs of the structure theorem for finitely generated modules over a PID - Mathematics Stack Exchange](https://i.stack.imgur.com/Ql5IE.jpg)
abstract algebra - Proofs of the structure theorem for finitely generated modules over a PID - Mathematics Stack Exchange
![principal ideal domains - Need help understanding a step in a proof about modules over PIDs - Mathematics Stack Exchange principal ideal domains - Need help understanding a step in a proof about modules over PIDs - Mathematics Stack Exchange](https://i.stack.imgur.com/T1IdY.png)
principal ideal domains - Need help understanding a step in a proof about modules over PIDs - Mathematics Stack Exchange
![abstract algebra - Let $M$ be a free module over a PID with finite rank, then any submodule $N \subset M$ is also free with finite rank - Mathematics Stack Exchange abstract algebra - Let $M$ be a free module over a PID with finite rank, then any submodule $N \subset M$ is also free with finite rank - Mathematics Stack Exchange](https://i.stack.imgur.com/XV1sd.png)
abstract algebra - Let $M$ be a free module over a PID with finite rank, then any submodule $N \subset M$ is also free with finite rank - Mathematics Stack Exchange
![abstract algebra - A finitely generated torsional free module A over a principal ideal domain is free - Mathematics Stack Exchange abstract algebra - A finitely generated torsional free module A over a principal ideal domain is free - Mathematics Stack Exchange](https://i.stack.imgur.com/d8QZS.jpg)
abstract algebra - A finitely generated torsional free module A over a principal ideal domain is free - Mathematics Stack Exchange
Assignment 10 – Part 1 – Math 611 (1) A torsion-free module over Z that is not free. Here is a good 'counterexample' to
6. Modules over Principal Ideal Domains. The aim of this chapter is to determine the structure of any finitely generated module
CHARACTERIZATION OF PRIME SUBMODULES OF A FINITELY GENERATED FREE MODULE OVER A PID 1. Introduction Throughout this paper R deno
Modules over a PID Hjalmar Rosengren, 20 October 2015 We will classify all finitely generated modules over a PID R. One very imp
STRUCTURE THEOREM OF FINITELY GENERATED MODULES OVER A PID Notation 1. For a left R-module M and x ∈ M, the (left) annihilator
![Correctness of the relation between free, torsion, torsion free, finitely generated module. - Mathematics Stack Exchange Correctness of the relation between free, torsion, torsion free, finitely generated module. - Mathematics Stack Exchange](https://i.stack.imgur.com/AeYpK.jpg)